| Forum » Off-topic » Riddles 'N' Jokes | Date | |
|---|---|---|
|
Username
3 msgs.
Ball boy
|
@Lifeguard said: There once were four devout EPL fans, one from Man City, Chelsea, Arsenal, and Man Utd, who decided that they would all jump off a cliff to appeal to the soccer gods for their team to win the league that year. Upon arriving at the edge of the cliff, the Chelsea fan said "This is for Chelsea!". And with that he jumped. The fan from Arsenal said "This is for the Gunners!", and he jumped next. The Man Utd fan said "This is for United!", and pushed the Man City fan over the edge ahhhhhahahahahahahahaha, good one |
05/02/2012 12:45 |
| - Div/Gr | ||
|
Username
2737 msgs.
Best scorer
|
I'm getting tired of studying, so i'll share a "riddle" with you guys: A gas detector is used to determine the concentration of flammable gas in a gas stream. Normally the gas concentration is 1% by volume, well below the alarm limit of 4% and the lower flammability limit of 5%. If the gas concentration is above the lower flammability limit, it is flammable. A particular gas detector demonstrates first-order behavior with a time constant of 5 s. At a particular time, the gas stream is flowing at 1 m3/s through a duct with a cross sectional area of 1 m2. If the gas concentration suddenly increases from 1% to 7% by volume, how many cubic meters of flammable gas pass the sensor before the alarm is sounded? HINT: If you show all steps, it will take you a bit more than a page of differential equations to find the answer  Edited by @solirocket 08-02-2012 08:58 |
08/02/2012 08:57 |
| - Div/Gr | ||
|
Username
290 msgs.
First-team player
|
@solirocket said: I'm getting tired of studying, so i'll share a "riddle" with you guys: A gas detector is used to determine the concentration of flammable gas in a gas stream. Normally the gas concentration is 1% by volume, well below the alarm limit of 4% and the lower flammability limit of 5%. If the gas concentration is above the lower flammability limit, it is flammable. A particular gas detector demonstrates first-order behavior with a time constant of 5 s. At a particular time, the gas stream is flowing at 1 m3/s through a duct with a cross sectional area of 1 m2. If the gas concentration suddenly increases from 1% to 7% by volume, how many cubic meters of flammable gas pass the sensor before the alarm is sounded? HINT: If you show all steps, it will take you a bit more than a page of differential equations to find the answer Edited by @solirocket 08-02-2012 08:58 wth.....XO.......lol so confusing |
08/02/2012 10:11 |
| - Div/Gr | ||
|
Username
908 msgs.
MVP of the game
|
0 zero since mine one the alarm had checked just when it started so no gas passes the duct | 08/02/2012 14:00 |
| - Div/Gr | ||
|
Username
6256 msgs.
Golden Ball
|
@solirocket said: I'm getting tired of studying, so i'll share a "riddle" with you guys: A gas detector is used to determine the concentration of flammable gas in a gas stream. Normally the gas concentration is 1% by volume, well below the alarm limit of 4% and the lower flammability limit of 5%. If the gas concentration is above the lower flammability limit, it is flammable. A particular gas detector demonstrates first-order behavior with a time constant of 5 s. At a particular time, the gas stream is flowing at 1 m3/s through a duct with a cross sectional area of 1 m2. If the gas concentration suddenly increases from 1% to 7% by volume, how many cubic meters of flammable gas pass the sensor before the alarm is sounded? HINT: If you show all steps, it will take you a bit more than a page of differential equations to find the answer Edited by @solirocket 08-02-2012 08:58 I think you just want us to do your homework Soli. |
08/02/2012 14:09 |
| - Div/Gr | ||
|
Username
4820 msgs.
Best scorer
|
.35m3 ?? | 08/02/2012 15:51 |
| - Div/Gr | ||
|
Username
2737 msgs.
Best scorer
|
answer is not zero, im not sure if you guessed or not bluegene, but you're close...the answer is 3.47 m3 | 09/02/2012 02:51 |
| - Div/Gr | ||
|
Username
4820 msgs.
Best scorer
|
I calculated 7% of gas outflow per sec. Which came out to .7/sec Then .7 * 5 sec = 3.5 |
09/02/2012 06:04 |
| - Div/Gr | ||
|
Username
2737 msgs.
Best scorer
|
hahaha, lucky guess...bad approach. You need to make a transfer function to relate, the actual concentration to the detected concentration. Then you plug in the laplace transform of your step function for the actual concentration in the transfer function. Then you take the inverse laplace transform of the transfer function and solve for t. btw, you dont multiply the time by the concentration, so if it was 5 seconds it would be 5m3. This is because the flammable gas is equally distributed among the whole volume and does not only take 7% of the volume. fun, isnt it? |
09/02/2012 07:12 |
| - Div/Gr | ||
|
Username
4820 msgs.
Best scorer
|
fun, isnt it? Unfortunately i have to agree to disagree. |
09/02/2012 13:15 |
| - Div/Gr | ||
4
